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triangle ABC  <B =?ab =root 7 ac =4 bc =6

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triangle ABC 

<B =?

ab =root 7

ac =4

bc =6

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Posted (Answer #1)

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Given triangle ABC with AB=`sqrt(7)` ,AC=4 and BC=6 find the measure of angle B:

Use the law of cosines: `c^2=a^2+b^2-2abcosC`






The angle has measure of approximately 20.4 degrees.

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