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If a transformer steps down a 120-V source to 6.3 V and is connected to an 8 ohm...
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When a load resistance is connected to the secondary of a transformer a part of it (which can be less or bigger then 1) is reflected back to the primary, and is seen by the voltage source that supply power to the primary coil.
To determine how much of the load resistance Rs is reflected into primary (seen as Rp by the voltage source Vp that drives the primary) we write down the Ohm's law:
`R_p = E_p/I_p = (n*E_s)/(I_s/n) = n^2*(E_s/I_s) = n^2*(U(Rs))/(I(Rs)) = n^2*R_s`
where n is the transformer rapport (otherwise said the turns ratio)
`n =n_p/n_s =E_p/E_s =120/6.3=19.05`
Therefore the reflected resistance of a load Rs =8 ohm back to the source is
`R_p =19.5^2*8 =2902.5 ohm =2.9 kohm`
Posted by valentin68 on September 9, 2013 at 10:49 AM (Answer #1)
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