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a train travels at a velocity of 50+ m/s.It takes 80 s to slow down to 5 m/s with...
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Elementary School Teacher
A train traveling 50 m/s reduces its velocity by 45 m/s over the course of 80 s. Assuming that the velocity change is constant we would find the rate of change by dividing the amount of change (45 m/s) by the time it took (80 s) `-45 m/s-:80s = -9/16` m/s^2. Since a rate of change in velocity is acceleration your rate of acceleration would be -9/16 m/s^2 or -0.5625 m/s^2.
Posted by tjbrewer on March 22, 2013 at 10:39 PM (Answer #1)
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