### 1 Answer | Add Yours

A train traveling 50 m/s reduces its velocity by 45 m/s over the course of 80 s. Assuming that the velocity change is constant we would find the rate of change by dividing the amount of change (45 m/s) by the time it took (80 s) `-45 m/s-:80s = -9/16` m/s^2. Since a rate of change in velocity is acceleration your rate of acceleration would be -9/16 m/s^2 or -0.5625 m/s^2.

### Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes