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A train travels along a straight horizontal track with constant acceleration. Points A,...
A train travels along a straight horizontal track with constant acceleration. Points A, B and C are on the track with B between A and C. The distance AB is 1200 m and the distance BC is 2500 m. As the train passes B, its speed is 26ms–1. The train takes 60 s to travel from A to B.
B) Determine the acceleration of the train?
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Previous part of this question is answered in;
According to the previous answer the velocity of the train at A is 14m/s. From A to B the train takes 60s to travel and at B the speed of the train is 26m/s. All this time the train has accelerated.
Acceleration of train `= (26-14)/60 = 12/60 = 0.2m/s^2`
So the acceleration of the train is `0.2m/s^2` .
Posted by jeew-m on August 6, 2013 at 9:07 AM (Answer #1)
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