A train travels along a straight horizontal track with constant acceleration. Points *A, B *and *C *are on the track with *B *between *A *and *C. *The distance *AB *is 1200 m and the distance *BC *is 2500 m. As the train passes *B, *its speed is 26ms–1. The train takes 60 s to travel from *A *to *B.*

a) Find the speed of the train as it passes *A*.

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See the image attached with the following calculations.

Let us say the speed of train at A is Vm/s.

It is given that the distance between A and B is 1200m

The area of the time velocity graph represents the distance travelled.

`(V+26)/2xx60 =1200`

`V+26 = 40`

`V=14`

*So the speed of the train at A is 14m/s*

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