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Math`g(x) = x4`, the the domain and range is given as follows (i)Domain definition: The domain of a function is the set of the input or argument values for which the function is real and defined. In...

Math`h(x) = x+3` , the the domain and range is given as follows (i)Domain definition: The domain of a function is the set of the input or argument values for which the function is real and defined....

Math`f(x) = x+2` , the the domain and range is given as follows (i)Domain definition: The domain of a function is the set of the input or argument values for which the function is real and defined....

Math`f(x) = x (1/4)` , the the domain and range is given as follows (i)Domain definition: The domain of a function is the set of the input or argument values for which the function is real and...

Math`f(x) = x+(1/2)` , the the domain and range is given as follows (i)Domain definition: The domain of a function is the set of the input or argument values for which the function is real and...

MathGiven f(x) = x if x<= 3 and f(x) = 2 if x>3 then, the graph of the g(x) is plotted in the graph below, and the domain of this function g(x) is all real numbers as the x values covers the...

MathGiven h(x) = 1 if x< 2 and h(x) = 1 if x> 2 the graph is given in the attachments the domain of the function f(x) is` (oo,2) U (2,oo)` and the range is a set {1, 1}

Mathf(x) = [[x]], the the domain and range is given as follows let x= 1.9 as x = 1.9,then f(x) = [[1.9]] = 1x=0 as x = 0,then f(x) = [[0]] = 0x= 0.9 as x = 0.9,then f(x) = [[0.9]] = 0x=...

Mathg(x) = [[x]], the the domain and range is given as follows let x= 1.9 then g(x) = 2 as [[x]] = 2x=0 then g(x) = 0 as [[x]] = 0x= 0.9 then g(x) = 1 as [[x]] = 1x= 1.2 then g(x) = 1 as [[x]]...

MathHi!The slope (m) as given in the question is 3 which means m=3. You are given points (2,4) through which the line passes. As you may recall, the slope intercept form is y=m*x+b, where: m=slope = 3...

MathGiven the line passes through the point `(x_1,y_1)=(0,2)` `(x_2,y_2)=(4,2)` so the slope is given as `m = (y_2  y_1)/(x_2  x_1) = (2(2))/(40) = 4/4 = 1` the slopeintercept form is y=...

MathGiven 3x5>=4 => 3x>=4+5 => 3x>= 9 => x>= 3 the solution set is as follows

Math28  6y <23 => 6y < 23 28 => 6y < 5 => 6y > 5 => y > 5/6 => y > 0.8333 the solution set is

Mathf(x) = [[x]], the the domain and range is given as follows let x= 1.9 then f(x) = 2 as [[x]] = 2x=0 then f(x) = 0 as [[x]] = 0x= 0.9 then f(x) = 1 as [[x]] = 1x= 1.2 then f(x) = 1 as [[x]]...

Mathf(x) = [[2x]], the the domain and range is given as follows let x= 1.9 then f(x) = 4 as [[x]] = 2x=0 then f(x) = 0 as [[x]] = 0x= 0.9 then f(x) = 2 as [[x]] = 1x= 1.2 then f(x) = 2 as [[x]]...

Math`f(x) = x4` , the the domain and range is given as follows (i)Domain definition: The domain of a function is the set of the input or argument values for which the function is real and defined....

Math`f(x) = 3x2` , the the domain and range is given as follows (i)Domain definition: The domain of a function is the set of the input or argument values for which the function is real and defined....

MathGiven g(x) = 1 [it is invalid .......assuming g(x) = x1] g(x) = x1 if x<0 and g(x) = x+2 if x> =0 the graph of the g(x) is plotted in the graph below, and the domain of this function g(x)...

MathGiven h(x) = x+3 if x<= 1 and h(x) = 2x if x> 1 the graph of the h(x) is plotted in the graph below, and the domain of this function h(x) is a set of real numbers as x<= 1 and x>...

Mathf(x) = [[x+3]], the the domain and range is given as followsf(x) = [[x]] +3 > from the property [[x+n]]= [[x]]+n let x= 1 then f(x) = 2 as [[x]] = 1x=0 then f(x) = 3 as [[x]] = 0x=...

MathGiven the points are `(x_1,y_1) =(5,0)` and `(x_2,y_2) =(4,0)` the slope of the line passing through the points is given as `m = (y_2  y_1)/(x_2  x_1)` `= (00)/(4(5))` ` = 0` so the...

MathThe answer is: No Solutions, why? Because there's no absolute value (or positive numbers) that will always be equal or less than a negative number.

Math`4x+7<= 31` => `4x <= 31  7` => `4x <= 24` on sign change we get => `4x >= 24` => `x >= 6`

Math`2(r4)+ 5 >= 9` => `2r  8 +5 >=9` => `2r  3 >= 9` =>` 2r >= 12` => `r>= 6`

MathIn the given set [138, 235, 976, 230, 412, 466] to find the median ,first we need to arrange the set of numbers in order, so, [138, 235, 976, 230, 412, 466] => [138, 230,235,412,466,976]...

Mathto find the median ,first we need to arrange the set of numbers in order, so, [2.5, 7.8, 5.5, 2.3, 6.2, 7.8] => [2.3 ,2.5 ,5.5 ,6.2 ,7.8,7.8] Here there are 6 numbers and so we don't have just...

MathGiven slope m= 3 and the line passes through the point (x,y)= (0, 6) the slopeintercept form of a line is y= mx+b from the above we know m = 3, so the line equation is y= 3x+b(1)...

MathGiven slope m= 0.25 and the line passes through the point (x,y)= (0, 4) the slopeintercept form of a line is y= mx+b from the above we know m = 0.25 = 1/4, so the line equation is y=...

MathGiven slope m= (1/2) and the line passes through the point (x,y)= (1,3) the slopeintercept form of a line is y= mx+b from the above we know `m = (1/2)` , so the line equation is `y= (1/2)x+b`...

MathGiven slope m= 3/2 and the line passes through the point (x,y)= (5,1) the slopeintercept form of a line is y= mx+b from the above we know m = 3/2, so the line equation is `y= (3/2)x+b`...

MathGiven slope m= 0.5 and the line passes through the point (x,y)= (2, 3) the slopeintercept form of a line is `y= mx+b` from the above we know ` m = 0.5 = (1/2)` , so the line equation is `y=...

MathGiven slope m= 4 and the line passes through the point (x,y)= (0, 0) the slopeintercept form of a line is y= mx+b from the above we know m = 4, so the line equation is y= 4x+b(1) we...

MathGiven the points are `(x_1,y_1) =(2,5)` and `(x_2,y_2) =(3,1)` the slope of the line passing through the points is given as `m = (y_2  y_1)/(x_2  x_1)` `= (15)/(3(2))` ` = 4/5` so...

MathGiven the points are `(x_1,y_1) =(7,1)` and `(x_2,y_2) =(7,8)` the slope of the line passing through the points is given as `m = (y_2  y_1)/(x_2  x_1)` `= (81)/(77)` ` = 7/0= oo` so the...

MathGiven the points are `(x_1,y_1) =(4,0)` and `(x_2,y_2) =(3,0)` the slope of the line passing through the points is given as `m = (y_2  y_1)/(x_2  x_1)` `= (00)/(3(4))` ` = 0/7 =0` so...

MathGiven the points are `(x_1,y_1) =(2,3)` and `(x_2,y_2) =(0,0)` the slope of the line passing through the points is given as `m = (y_2  y_1)/(x_2  x_1)` `= (0  (3))/(0(2))` ` = 3/2`...

MathUsing the intercept method first we will find the intercept form of the line the intercept form is `x/a +y/b = 1` where a and b are the x and y intercepts respectively as given x intercept...

MathUsing the intercept method first we will find the intercept form of the line the intercept form is `x/a +y/b = 1` where a and b are the x and y intercepts respectively as given x intercept 1/3,...

MathGiven the line is y = (2/3) x + 5 ` ` and the slope of the line is m_1 = 2/3` ` as we know that the slopes of two parallel lines are equal let the slope of the required line is m_2 so ,...

MathGiven an equation of a line L1 is y = 1/4 x + 7 y = 1/4 x + 7 so the slope of the line L1 be m_1 is = 1/4 as we know that the product of the slopes of the two perpendicular lines is equal to 1...

MathGiven an equation of a line L1 is 3x  1/5 y = 3 3x  (1/5) y = 3 =>  (1/5) y = 3  3x => (1/5) y = 3x  3 => y =5(3x  3) => y = 15 x  15 so the slope of the line L1 be m_1 is =...

MathGiven a line L1 (let us assume) passes through (3, 1) and is parallel to the line L2 (let us assume) that passes through (3, 3) and (0, 6). we need to find the equation of L1? sol: First we need...

MathGiven the points are (x_1,y_1)=(0, 3) and (x_2,y_2)=(4, 1) so the slope of the points is m = (y_2  y_1)/(x_2  x_1) = (1(3))/(40) = 4/4 = 1 as the line passes through the point (4,1) and...

MathGiven the points are `(x_1,y_1) =(7,2)` and `(x_2,y_2) =(5,6)` the slope of the line passing through the points is given as `m = (y_2  y_1)/(x_2  x_1)` `= (62)/(57)` `= 4/(2) = 2`...

MathGiven the points are (x_1,y_1) =(1,3) and (x_2,y_2) =(3,3) the slope of the line passing through the points is given as m = (y_2  y_1)/(x_2  x_1) = (3(3))/(31) = 6/2 = 3 so the slope...

MathIn general the slope and intercept of y=mx+b is m is the slope and b is the yintercept. The above equation the slope is m=2 and b=5 is y intercept

MathHello!You are given the equation 3x+2y10=0 As you may recall, the slope intercept form is y=m*x+b, where: m=slope b=constant = ?(you have to figure it out!) So all you really have to do is...

MathGiven slope m= 0.5 and the line passes through the point (x,y)= (6,4) the slopeintercept form of a line is `y= mx+b` from the above we know` m = 0.5 = (1/2)` , so the line equation is `y=...

MathGiven slope m= 3/4 and the line passes through the point (x,y)= (2 ,1/2) the slopeintercept form of a line is `y= mx+b` from the above we know` m = 3/4` , so the line equation is `y=...

MathGiven the points are `(x_1,y_1) =(6,1)` and `(x_2,y_2) =(8,4)` the slope of the line passing through the points is given as `m = (y_2  y_1)/(x_2  x_1)` `= (41)/(86)` ` = 3/2` so the...