# Math Homework Help

### Showing All Questions Answered Popular Recommended Unanswered Editor's Choice in Math

• Math
Hello! Let's write an equation of the straight line which goes through the first two points. Then the third point lies on this line if and only if its coordinates satisfy the equation. For two...

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• Math
There are various answers in which this could be the case. However, since the domain of h(x) must be [0,  then this means that the domain of either f(x) or g(x) must also have the same...

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• Math
Hello! Denote the cost of supplies for a dog as d and for a cat as c (in dollars). Then the first condition may be written in terms of d and c as d=2*c. The second condition is 24*d+155*c=1152....

• Math
You need to write the characteristic equation, such that: r^2 - (1/2)r + 1/16+x-e^x = 0 You need to evaluate Delta , such that: Delta = (-1/2)^2 - 4(1/16+x-e^x) = 1/4 - 1/4 - 4x + 4e^x Delta...

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• Math
Because it is cheaper to have books shipped to San Francisco from Novato you would have all 600 shipped from there as it is only \$5 per text. Also it is cheaper to have books shipped to Sacramento...

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• Math
Hello! Denote the smaller angle as alpha, alpha =17°, and the larger one as beta, beta=21.8°. Then from the right triangle BAO by the definition of tangent x/y=tan(alpha). And from the...

• Math
Hello! Your question is very short and I might misunderstand it. I think you mean a Cartesian product of the set of all real numbers RR and the set consisting of one element, the number 2. It is,...

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• Math
Solve 4x+3y=-5; 3x-2y=-9 by elimination: Elimination (or multiplication/addition or linear combinations) is a method that adds/subtracts multiples of one equation to multiples of the other...

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• Math
We have to be careful here because of absolute value sign. We need to know where the function under absolute value changes sign (in the interval of integration), which is at x=pi in this case....

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• Math
Hello! Find the indefinite integral: int((sqrt(y)-y)/y^2)dy=int(y^(-3/2)-1/y)dy=(-2)*y^(-(1)/(2))-ln(y). Then substitute y from 1 to 4: (-2*4^(-1/2)-ln(4))-(-2)=-1-ln(4)+2=1-ln(4) approx -0.386.

Asked by enotes on via web

• Math
Hello! First find the indefinite integral, int(x/(2)-2/x)dx=int(x/2)dx-int(2/x)dx=(x^2)/4-2ln(x). Then substitute x from 1 to 2: (2^2/4-2ln(2))-(1^2/4-2ln(1))=1-2ln(2)-1/4=3/4-2ln(2) approx...

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• Math
You need to evaluate the integral, hence, you need to use the fundamental theorem of calculus, such that: int_a^b f(x)dx = F(b) - F(a) int_0^1(5x - 5^x)dx = int_0^1(5x)dx - int_0^1 5^x dx...

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• Math
You need to evaluate the integral, hence, you need to use the fundamental theorem of calculus, such that: int_a^b f(x)dx = F(b) - F(a) int_0^1(x^10 + 10^x)dx = int_0^1(x^10)dx + int_0^1 10^x...

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• Math
You need to evaluate the definite integral using the fundamental theorem of calculus, such that: int_a^b f(u) du = F(b) - F(a) int_(pi/4)^(pi/3) csc^2 theta d theta = int_(pi/4)^(pi/3) 1/(sin^2...

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• Math
You need to evaluate the definite integral using the fundamental theorem of calculus, such that: int_a^b f(x)dx = F(b) - F(a) int_0^(pi/4)(1+cos^2 theta)/(cos^2 theta) d theta =...

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• Math
Before evaluating this integral, simplify the expression in the integral using trigonometric identities. The following Pythagorean identity will be useful: tan^2(theta) + 1 = sec^2(theta) Start...

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• Math
We will make substitution x=t^6. Therefore, the differential is dx=6t^5dt and the new bounds of integration are t_1=root(6)(1)=1 and t_2=root(6)(64)=2. int_1^64(1+root(3)(x))/sqrt x...

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• Math
Hello! Consider the denominator first: sinh(x)+cosh(x)=(e^x-e^(-x))/(2) +(e^x+e^(-x))/(2)=e^x. Therefore the integrand is equal to 2 and the integral is 2*(10-(-10))=40.

Asked by enotes on via web

• Math
Hello! This integral is a table one, int(dr)/(sqrt(1-r^2))=arcsin(r)+C.   Therefore the definite integral is equal to arcsin(sqrt(3)/2)-arcsin(0)=pi/3-0=pi/3 approx 1.047. =arcsin(r)+C.

Asked by enotes on via web

• Math
You need to evaluate the definite integral using the fundamental theorem of calculus, such that: int_a^b f(x)dx = F(b) - F(a) You need to expand the cube such that: (x-1)^3 = x^3 - 1 - 3x(x-1)...

Asked by enotes on via web

• Math
Hello! (t^2-1)/(t^4-1)=1/(t^2+1). Therefore indefinite integral is arctan(t)(+C). Substitute t from 0 to 1/sqrt(3) and obtain arctan(1/sqrt(3))-arctan(0)=pi/6-0=pi/6 approx 0.524.

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• Math
We have to be careful because of the absolute value. We need to know where the function under absolute values is positive and when it is negative in the given interval. It is also a good idea to...

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• Math
Hello! Consider two intervals: (-1, 0) and (0, 2) to simplify |x|: int_(-1)^2(x-2|x|)dx=int_(-1)^0(x-2|x|)dx+int_0^2(x-2|x|)dx= =int_(-1)^0(x+2x)dx+int_0^2(x-2x)dx=...

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• Math
You need to find the indefinite integral, hence, you need to remember that sec t = 1/(cos t) , such that: int (sec t)(sec t + tan t) dt = int (1/(cos t))(1 + sin t)/(cos t) dt int (sec t)(sec...

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• Math
You need to find the indefinite integral, hence, you need to remember that 1 + tan^2 x = 1/(cos^2 x) = (tan x)'. int (1 + tan^2 x )dx = int (tan x)' dx = tan x + c Hence, evaluating the...

Asked by enotes on via web

• Math
You need to find the indefinite integral, hence, you need to remember that sin 2x = 2sin x*cos x , such that: int (sin 2x)(sin x) dx = int (2sin x*cos x)/(sin x) dx  int (sin 2x)(sin x) dx =...

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• Math
You need to evaluate the integral, hence, you need to use the fundamental theorem of calculus, such that: int_a^b f(x)dx = F(b) - F(a) int_(-2)^3(x^3 - 3)dx = int_(-2)^3(x^3)dx - int_(-2)^3 3...

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• Math
You need to evaluate the integral, hence, you need to use the fundamental theorem of calculus, such that: int_a^b f(x)dx = F(b) - F(a) int_1^2(4x^3 - 3x^2 + 2x)dx = int_1^2(4x^3)dx - int_1^2...

Asked by enotes on via web

• Math
You need to evaluate the definite integral using the fundamental theorem of calculus, such that: int_a^b f(x)dx = F(b) - F(a) int_(-2)^0 ((1/2)t^4 + (1/4)t^3 - t)dt = int_(-2)^0 ((1/2)t^4 dt +...

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• Math
We will use linearity of integral: int(a cdot f(x)+b cdot g(x))dx=a int f(x)dx+b int g(x)dx. int_0^3(1+6w^2-10w^4)dw=int_0^3dw+6int_0^3w^2dw-10int_0^3w^4dw=...

Asked by enotes on via web

• Math
We have to evaluate the integral: \int_{0}^{2}(2x-3)(4x^2+1)dx=\int_{0}^{2}(8x^3-12x^2+2x-3)dx =[8(x^4/4)-12(x^3/3)+2(x^2/2)-3x]_{0}^{2}...

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• Math
You need to use the following substitution to evaluate the definite integral, such that: 1 - t = u => -dt = du int_(-1)^1 t*(1-t)^2dt = int_(u_1)^(u_2) (1 - u)*u^2 (-du) int_(u_1)^(u_2) (u...

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• Math
You need to evaluate the definite integral using the fundamental theorem of calculus, such that: int_a^b f(x)dx = F(b) - F(a) int_0^pi (5e^x+ 3sin x)dx = int_0^pi 5e^x dx + int_0^pi 3sin x...

Asked by enotes on via web

• Math
You need to evaluate the definite integral using the fundamental theorem of calculus, such that: int_a^b f(x)dx = F(b) - F(a) int_1^2 (1/x^2 - 4/x^3)dx = int_1^2 1/x^2 dx - int_1^2 4/x^3 dx...

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• Math
int_1^4(4+6u)/sqrt(u)du =int_1^4(4/sqrt(u)+(6u)/sqrt(u))du =int_1^4(4u^(-1/2)+6u^(1/2))du =[4(u^(-1/2+1)/(-1/2+1))+6(u^(1/2+1)/(1/2+1))]_1^4 =[4(u^(1/2)/(1/2))+6(u^(3/2)/(3/2))]_1^4...

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• Math
You need to evaluate the definite integral using the fundamental theorem of calculus, such that: int_a^b f(x)dx = F(b) - F(a) int_0^4(3sqrt t - 2e^t)dt = int_0^4 3sqrt tdt - int_0^4 2e^t...

Asked by enotes on via web

• Math
You need to evaluate the definite integral, such that: int_0^1 x(root(3) x + root(4) x)dx = int_0^1 (x^(1+1/3) + x^(1+1/4))dx int_0^1 x(root(3) x + root(4) x)dx = ((x^(2+1/3))/(2+1/3) +...

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• Math
You need to evaluate the indefinite integral, such that: int f(x)dx = F(x) + c int (x^2 - x^(-2))dx = int (x^2)dx - int x^(-2) dx  Evaluating each definite integral, using the formula int x^n...

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• Math
int sqrt(x^3)root(3)(x^2) dx Before evaluating, convert the radicals to expressions with rational exponents. = int x^(3/2)*x^(2/3) dx Then, simplify the integrand. Apply the laws of exponent...

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• Math
int (x^4-1/2x^3+1/4x-2)dx To evaluate this integral, apply the formulas int x^n dx=x^(n+1)/(n+1) +C and int adx = ax + C . int (x^4-1/2x^3+1/4x-2)dx =x^5/5 - 1/2*x^4/4 + 1/4*x^2/2-2x...

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• Math
int (y^3+1.8y^2-2.4y)dy To evaluate this integral, apply the formula int x^n dx = x^(n+1)/(n+1) + C . = y^4/4 + 1.8y^3/3 - 2.4y^2/2 + C =0.25y^4 + 0.6y^3 - 1.2y^2 + C Therefore, ...

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• Math
You need to evaluate the indefinite integral, hence, you need to open the brackets, such that: (u+4)(2u+1) = 2u^2 + 9u + 4 int (u+4)(2u+1) du = int (2u^2 + 9u + 4) du  int (u+4)(2u+1) du =...

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• Math
intv(v^2+2)^2dv =intv((v^2)^2+2v^2*2+2^2)dv =intv(v^4+4v^2+4)dv =int(v^5+4v^3+4v)dv apply the power rule, =v^6/6+4v^4/4+4v^2/2+C , C is constant =v^6/6+v^4+2v^2+C

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• Math
int(x^3-2sqrt(x))/xdx Simplify by dividing each term in the numerator by x.  <br>  =(x^3/3)-(2x^(1/2))/(1/2)+C =(x^3/3)-4x^(1/2)+C  

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• Math
int(x^2+1+1/(x^2+1))dx apply the sum rule, =intx^2dx+int1dx+int1/(x^2+1)dx To evaluate the above integrals, we know that, intx^ndx=x^(n+1)/(n+1) and int1/(x^2+1)dx=arctan(x) using above,...

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• Math
We have to find the integral : \int (sin(x)+sinh(x) )dx=-cos(x)+cosh(x)+C where C is a constant.

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• Math
int(csc^2(t)-2e^t)dt Apply the sum rule, =intcsc^2(t)dt-int(2e^tdt We now the following common integrals, intcsc^2(x)=-cot(x) and inte^xdx=e^x evaluate using the above, =-cot(t)-2e^t+C...

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• Math
You need to evaluate the indefinite integral, such that: int f(theta)d theta = F(theta) + c int (theta - csc theta* cot theta)d theta = int theta d theta - int (csc theta* cot theta)d theta...

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• Math
y=sec^2(x) Refer the graph in the attached image. From the graph, Area of the region beneath the curve ~~ 4/10(Area of the Rectangle) Area of the region=~~(4/10)(pi/3*4) Area of the...

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We have to evaluate the integral and interpret as difference of areas. So, \int_{-1}^{2}x^3dx=[x^4/4]_{-1}^{2} =[(2^4)/4]-1/4 =16/4-1/4 =15/4=3.75 So...