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At time t = 0, Car A, which is travelling at a constant speed of 20 ms–1 on a straight horizontal road, overtakes Car B travelling at a speed of 15 ms–1. Car B immediately accelerates uniformly and, T seconds later, it overtakes Car A, which has kept its speed at 20 ms–1. The distance travelled by each car in time T is 600 m.
Find the speed of car B at the moment it overtakes car A.
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Since speed of the car remains unchanged 20ms^(-1)
Car A travelld 600 m in T sec
Apply equation linear motion
since speed remains same so , a=0 ,Thus
600=20 x T
Acceleration for car B
Thus when car B was overtaking car A ,its speed will be determined by third equation of motion
Thus when car B overtook car A ,its speed was 25m/s
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