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Three lines intersect at a point and are mutually perpendicular. If the first two lines...

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hockeyfan54 | Student | Salutatorian

Posted March 13, 2013 at 10:51 PM via web

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Three lines intersect at a point and are mutually perpendicular. If the first two lines are

L_1 : ((x+32)/4)= ((y-4)/-1) = ((z+13)/(2))  L_2 : (12,283,133) + t<1,36,16>

then find the equation of the third line.

L_3 : (x,y,z)=

Enter your answer in the form (x_0,y_0,z_0)+<a,b,c)t with t as your parameter.

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