Three lines intersect at a point and are mutually perpendicular. If the first two lines are
L_1 : ((x+32)/4)= ((y-4)/-1) = ((z+13)/(2)) L_2 : (12,283,133) + t<1,36,16>
then find the equation of the third line.
L_3 : (x,y,z)=
Enter your answer in the form (x_0,y_0,z_0)+<a,b,c)t with t as your parameter.
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