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Three four-sided (tetrahedral) dice are thrown together. Each dieis labelled with...

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ioannak | eNotes Newbie

Posted April 27, 2013 at 5:24 PM via web

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Three four-sided (tetrahedral) dice are thrown together. Each die
is labelled with 1,2,3,4 on its four sides. Find the probability of
obtaining all fours.

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted April 27, 2013 at 5:36 PM (Answer #1)

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Three four-sided (tetrahedral) dice are thrown together. Each die
is labeled with 1,2,3,4 on its four sides. Of the four values the probability of a die turning up 4 is 1/4 = 0.25

The probability of all the four dice turning up 4 is (1/4)^4 = 1/256

The required probability is 1/256.

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ioannak | eNotes Newbie

Posted April 27, 2013 at 5:54 PM (Answer #2)

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Three four-sided (tetrahedral) dice are thrown together. Each die
is labeled with 1,2,3,4 on its four sides. Of the four values the probability of a die turning up 4 is 1/4 = 0.25

The probability of all the four dice turning up 4 is (1/4)^4 = 1/256

The required probability is 1/256.

Find the probability of obtaining at least one ‘triple four’ in four
tosses of the three dice. [6]
(b) In order to decide who will play first in a certain board game, each
player rolls a four-sided die; the player with the highest score begins.
(i) What is the probability that two particular people obtain the
same score? [1]
(ii) Three people decide to play the game. What is the probability
that when they roll the die to decide who starts, they all obtain
different scores?

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