1 Answer | Add Yours
We are asked to graph a histogram for the data 17,19,20,21,23,23,24,30,33,40 -- the class width is to be 5.
You really do not need a graphing calculator for this. We need to first make a frequency distribution.
The least data point is 17 and the greatest is 40. The graph given asks us to start with a class interval of 15-19; the classes are 15-19,20-24,25-29,30-34,35-39,40-44. Note that each class has width 5 (15-16-17-18-19 etc...) Now we just count how many data points are in each interval:
After you establish the classes, you can count the data points using tally marks, etc...
** Technically the intervals are `14.5<=xlt19.5,19.5<=x<24.5` etc... **
The frequency of each interval (the number of data points in the class) is the height of the bar, the width is 5 for every class. (This is important, only the height changes.)
The graph looks something like this:
We’ve answered 315,806 questions. We can answer yours, too.Ask a question