What is the distance between the point P and the top of the pyramid?
Consider a pyramid that has as its base an equilateral triangle with sides 100m each. Its three lateral faces are identical isosceles triangles with sides 500m each. From a point P on the ground (on the same plane as the base) the angle of elevation of the top of the pyramid is 30°. Find the distance of the point P from the top of the pyramid.
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The distance from the centre of the pyramid to an apex (corner) of the base is given by
`d = 50/cos(30) = 57.7`
The height of the pyramid squared `h^2` is given by the length of one of the ridges squared minus `d_1^2`
ie, `h^2 = 500^2 - d_1^2`
`implies ` `h = sqrt(500^2 - d_1^2) = 497`
The distance of `P` from the top of the pyramid is then given by
` ``p = h/tan(30) = 860.233m`
The distance between P and the top of the pyramid is 860.233m
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