This is a curved line.When x=-3,y=x^2-4.There are seven points on the line and the seventh point is  x=3.So,draw the tangent at x=-2 and find its gradient.Thanks



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Posted on (Answer #1)

Given equation of the curve

`y=x^2-4`     (i)

differentiate (i) with respect to x

we have



Thus gradient (slope)=-4

The equation of tangent at `(x_1,y_1)`  and slope m is .


when x=-2 then y=0

Thus equation of tangent at (-2,0)  and slope -4 is




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