there are 3 piles of rocks, A,B,C where B has 2 more than A and C has 4 times as many rocks as A. The total number of rocks is 14. Find the number of rocks in each pile using x .

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There are 3 piles of rocks, A, B and C where B has 2 more than A and C has 4 times as many rocks as A. The total number of rocks is 14.

Let the number of rocks in A be x, C has 4 times as many rocks as A. This puts the number of rocks in C as 4x. B has two rocks more than A, this puts the number of rocks in B as x + 2.

As the total number of rocks is 14, 4x + x + 2x = 14

=> 7x = 14

=> x = 2

**The number of rocks in pile A, B and C is 2, 4 and 8 resp.**

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