There are 2 boxes one of them is 4•4•4 and the other is 12•12•12 how many times is the surface area of the larger cube?

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Let x = the length of small cube's sides = 4

Let y= the length of the large cube's sides = 12

The formula for the surface area of a cube is as follows:

`SA = 6a^2` , where a is the length of each side

We wish to know how many times larger the surface area of the bigger cube is of the smaller cube:

`n = (6y^2)/(6x^2)`

`=(6(12)^2)/(6(4)^2)`

`=864/96`

`=9`

Therefore, the surface area of the larger cube is 9 times bigger than the smaller cube.

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