# The test statistic in a right tailed test is z=2.50, use the given information to find the p-value. state the conclusion about the null hypothesis

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When the z-score is given, the p-value can be estimated using the formula `int_(-oo)^z 1/sqrt (2*pi)*e^(-u^2/2) du`

For a z-score of 2.5, the corresponding p-value is 0.0062

This is a very small value less than 0.01 or even 0.05 and it usually leads to the rejection of the null hypothesis.

**Due to the extremely small p-value the null hypothesis is rejected.**

**Sources:**