1 Answer | Add Yours
When the z-score is given, the p-value can be estimated using the formula `int_(-oo)^z 1/sqrt (2*pi)*e^(-u^2/2) du`
For a z-score of 2.5, the corresponding p-value is 0.0062
This is a very small value less than 0.01 or even 0.05 and it usually leads to the rejection of the null hypothesis.
Due to the extremely small p-value the null hypothesis is rejected.
We’ve answered 333,514 questions. We can answer yours, too.Ask a question