The ten's digit of a two digit exceeds its unit's digit by 4.If the ten's digit and the unit's digits are in the ratio 3:1, find the number.

ANSWER =62

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Let us say ten's digit is 'a' and unit's digit is 'b'. Then the number will be 'ab'

According to the given data;

`a-b = 4 ----(1)`

`a:b = 3:1 rarr a/b = 3/1 rarr a = 3b`

From (1)

`a-b = 4`

`3b-b = 4`

`b = 2`

`a-b = 4`

`a-2 = 4`

`a = 6`

*So the number is 62.*

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