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(t-5)(5t-3)

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dahirgallo | Student, Grade 9 | eNotes Newbie

Posted September 30, 2012 at 4:32 PM via web

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(t-5)(5t-3)

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sciencesolve | Teacher | (Level 3) Educator Emeritus

Posted September 30, 2012 at 4:44 PM (Answer #1)

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The request of the problem is vague, hence, supposing that you need to multiply the brackets yields:

`(t-5)(5t-3) = t*5t + t*(-3) - 5*(5t) - 5*(-3)`

`(t-5)(5t-3) = 5t^2 - 3t - 25t + 15`

`(t-5)(5t-3) = 5t^2 - 28t + 15`

Hence, evaluating the product of brackets yields `(t-5)(5t-3) = 5t^2 - 28t + 15` .

If the problem requests to solve for t the equation `(t-5)(5t-3) = 0` ,then you need to perform the following steps such that:

`(t-5)(5t-3) = 0 => {(t-5=0),(5t-3 = 0):} => t = 5 , t = 3/5`

Hence, evaluating the solutions to the equation yields `t = 5 , t = 3/5.`

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tub51463 | Middle School Teacher | eNoter

Posted September 30, 2012 at 10:04 PM (Answer #2)

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(t-5)(5t-3)

You have to use the FOIL method

F: first

    t*5t = 5t^2

O: outr

    t*-3 = -3t

I: inner

    -5*5t = -25t

L: last

    -5*-3 = 15

now put it all together:

     5t^2 - 3t - 25t + 15

     5t^2 - 28t + 15

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aa42 | Student, Grade 10 | eNoter

Posted October 1, 2012 at 7:39 PM (Answer #3)

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Multiplying (5t-3)and (t-5)\

                      5t - 3

                X      t - 5

                  -25t - 15

                5t^2-3T  X

             5t^2-28t+15

We get 5t^2-28t+15 which is the required answer.

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