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Suppose the probability that a U S resident has traveled to Canada is 0.18 to Mexico is...
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Let a U S resident travelling to Canada be an event A and to Mexico event B.
Corresponding probabilities are P(A) and P(B) respectively.
The probability that a U S resident travelling to both countries is given by P(A `nn` B).
We have to find the probability that an American chosen at random has travelled together to Canada or Mexico which is given by P(A `uu ` B).
Addition theorem of probability for two events states that “If A and B are two events associated with a random experiment, then P(A `uu` B) =P(A) + P(B) - P(A `nn` B).”
Putting the values:
P(A `uu` B) = 0.18+0.09-0.04
Therefore, the probability that an American chosen at random has travelled together Canada or Mexico is 0.23.
Posted by llltkl on June 28, 2013 at 12:36 AM (Answer #1)
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