If *n *represents the smaller of these two integers, which is an equation that can be used to find *n*? The sum of two consecutive even integers is 294.

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The sum of two consecutive even numbers is 294. If the smaller number is n, the larger number is n + 2. To determine n, solve the equation n + n + 2 = 294 for n.

Or 2n + 2 = 294

n = 146

**The equation to be solved to determine n is 2n + 2 = 294**

Given :- sum of the two even intefers = 294 and

The smaller of the two integer is n

The larger integer = n + 2 [ enen numbers differ by 2 ]

since sum of these two even integer = 294

That is, n + n + 2 = 294

=> 2n + 2 = 294

=> 2(n + 1) = 294

=> ( n + 1)= 294/2 = 147

=> n + 1= 147

=> **n = 146 <-- Answer**

Since the smaller number is "n" and the larger number is a consecutive even version, then the larger number would be "n+2"

So the equation would be

n+(n+2)=294

and then you simplify to get the answer...like this:

2n+2=294

2n=292

n=146

As n is the smaller of the two consective even integers, therefore the second integer is n+2.

Sum of the two numbers is n + n+2 which is also equal to 294

So the equation to be used to fine the numbers is: n+n+2 = 294

which reduces to 2n+2 =294

**The required equation is 2n+2 = 294 to find n.**

The above equation yields n= 146 and the two integers are 146, 148

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