The sum of the third and fourth terms in a sequence of consecutive integers is 47. what is the sum of the first five terms of the sequence.

### 1 Answer | Add Yours

Let us say the integers start from integer n.

Then the sequence is n, (n+1), (n+2).......

According to the given data;

`(n+2)+(n+3) = 47`

`2n+5 = 47`

`n = 21`

Sum of first five terms `= 21+22+23+24+25 = 115` ` `

*So the sum of first five terms is 115.*

*Note:*

*If we have to get the sum of large number of terms we can use arithmetic progression instead of the above method.*

### Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes