The sum of the third and fourth terms in a sequence of consecutive integers is 47. what is the sum of the first five terms of the sequence.

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Posted on

Let us say the integers start from integer n.

Then the sequence is n, (n+1), (n+2).......

According to the given data;

`(n+2)+(n+3) = 47`

`2n+5 = 47`

`n = 21`

Sum of first five terms `= 21+22+23+24+25 = 115` ` `

So the sum of first five terms is 115.

Note:

If we have to get the sum of large number of terms we can use arithmetic progression instead of the above method.

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