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The sum of the third and fourth terms in a sequence of consecutive integers is 47. what...
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Let us say the integers start from integer n.
Then the sequence is n, (n+1), (n+2).......
According to the given data;
`(n+2)+(n+3) = 47`
`2n+5 = 47`
`n = 21`
Sum of first five terms `= 21+22+23+24+25 = 115` ` `
So the sum of first five terms is 115.
If we have to get the sum of large number of terms we can use arithmetic progression instead of the above method.
Posted by jeew-m on September 25, 2013 at 5:41 AM (Answer #1)
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