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The sum of the ages of Frank and John is 54 years. 2 years ago, Frank was 4 times as...
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Right now, Frank + John = 54.
1) F + J = 54
But 2 years ago, Both Frank and John were 2 years younger each, which meant the sum of their ages is different by 4 years
2) F + J = 54 - 4 = 50
And 2 years ago, Frank was 4 times older than John
3) F = 4J
If we substitute eq. 3 for F in eq 2, we have
4) 4J + J = 50
5) 5J = 50
6) J = 10
But John was 10 2 years ago, so now his age is 12. Substituting his current age in eq. 1
7) F + 12 = 54
8) F = 42, so currently Frank is 42 and John is 12. Two years ago, Frank was 40 and John 10.
Posted by enotechris on January 29, 2009 at 6:10 AM (Answer #1)
Right now, F+J = 54 years
But two years ago, both of them were two years younger than now, so the sum of their age would be different by four years, so:
F+J= 54-4=50 years - eqn 1
Also, Frank was four times as old as John so:
F= 4J - eqn 2
Sub eqn 2 to eqn 1
Since John was age of 10 two years earlier, so his present age would be 10+2= 12 years.
So, now the earlier eqn would look like that
F=42. Thus, frank is 42 years of age while John is 12 years of age.
Posted by revolution on July 31, 2010 at 10:11 PM (Answer #2)
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