A submarine is being followed by two ships, A and B, 3.8km apart, with A due east of B. If A is on a bearing of 165 degrees from the submarine and B is on a bearing of 205 degrees from the submarine, find the distance from the submarine to both ships.
The answer is 5.7km and 5.4km
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Given `AB=3.8` Km (please refer to the attached image)
Since, `ltNSA=165^o` , then `ltESA=ltA=75^o`
Since, major`ltNSB` `=205^o` , <ASB=`40^o`
In `Delta BSA` , `ltB=(180-40-75)=` `65^o`
Applying law of sines we get:
Therefore, A to S`~~` 5.4 Km and B to S`~~` 5.7Km.
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