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 A string is divided into three segments, so that thesegments possess fundamental...

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tinacullen-13 | Student, Undergraduate | Honors

Posted May 27, 2013 at 11:32 AM via web

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 A string is divided into three segments, so that the
segments possess fundamental frequencies in the ratio
1 : 2 : 3. Then the lengths of the segments are in the
ratio

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pramodpandey | College Teacher | Valedictorian

Posted May 27, 2013 at 2:28 PM (Answer #1)

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We know

`nu=(1/(2pi))sqrt(g/l)`

`` Let  `k=(1/2pi)sqrt(g)`

`nu=k/sqrt(l)`

`nu sqrt(l)=k`

`nu_1:nu_2:nu_3=1:2:3`

`nu_1 sqrt(l_1)=nu_2sqrt( l_2)=nu_3sqrt( l_3)=k`

`sqrt(l_1)=sqrt(l_2).2`

`l_1/l_2=4/1`

`2sqrt(l_2)=3sqrt(l_3)`

`l_2/l_3=9/4`

`l_1:l_2:l_3=36:9:4`

`` where l_1,l_2 and l_3 are lengths of string.

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tinacullen-13 | Student, Undergraduate | Honors

Posted May 27, 2013 at 4:05 PM (Reply #1)

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but the awnser to the question is  given 6:3:2.

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pramodpandey | College Teacher | Valedictorian

Posted May 29, 2013 at 11:14 AM (Answer #2)

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you are right but actually you work out problem then see what is answer.May possible printing error or else ?

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tinacullen-13 | Student, Undergraduate | Honors

Posted May 29, 2013 at 1:20 PM (Reply #1)

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maybe there is printing mistake.please can you explain to me the question i asked before on height of the building

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