A straight line has equation y=3/2x + 6
write down the coordinates of a point that lies on the line and find the x intercept of the line
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The coordinates of ANY point that lies on the line?
If x-coordinate of a point on the line is x = 2, then y-coordinate has to be
`y = 3/2 * 2 + 6 = 3+6=9`
(2, 9) is a point on the line
x-intercept is the poipnt where the line intersects the x-axis. This means the y-coordinate of this point is y = 0. The x-coordinate can be found by plugging in y =0 into the equation of the line:
`0 = 3/2 x + 6`
`x=-12/3 = -4`
The x-intercept of this point is (-4,0).
To find the coordinates of a point on the line, all you have to do is pick a value for "x" and plug it into the equation, the resulting number will be the "y' in your coordinate.
1) Choose a value for x. Let's try 0. Plug in for x and solve for y.
y = 3/2x + 6
y = 3/2(0) + 6
y = 0 + 6
y = 6
2) One of the points on the line is (0,6). You can do this with any value for x. I just chose "0" because it was the nicest and easiest to plug in.
To find the x-intercept:
Remember that the x-intercept is the point where the line cross the x-axis. If you remember you graphing, the "y" of the coordinate will always be 0. So plugging a "0" in for y and solving for x will give me the x-intercept.
1) Plug in a "0" for y. Solve for x.
y = 3/2x + 6
0 = 3/2x + 6
-6 = 3/2x
*With a calculator, type in -6 / (3/2)**
x = -4.
The x-intercept is (-4,0).
Hope this helps! Good luck!
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