Starting with 1M glucose solution and distilled water, explain how you would make 100 ml of a .01M glucose solution.

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This is a dilution problem wherein we are looking how much volume of the stock solution we need to dilute. We have:

`M_1V_1 = M_2V_2`

- `M_1` = 1M
- `V_1` = ?
- `M_2` = 0.01 M
- `V_2` = 100mL = 0.100L *

`M_1V_1 = M_2V_2`

`(1)*V_1 = (0.01)*(0.100)`

`V_1 = ((0.01)*(0.100))/1`

`V_1 = 0.001L = 1 mL`

Answer: To prepare the said solution, we need to measure 1mL of the stock solution (1M glucose solution). Transfer the solution into a flask then add distilled water until it reaches 100mL mark.

*For proper computation, the volume units is converted from mL to L. 1000 mL = 1L

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