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If a standard parabola (y = x^2) is moved such that the new vertex is (-2,-4) and the...
If a standard parabola (y = x^2) is moved such that the new vertex is (-2,-4) and the point (1,1) becomes (1,-5), what will the equation of the new parabola be?
a) y = -(3(x+2))^2 - 4
b) y = -(3(x - 2))^2 + 4
c) y = -1/3(x + 2)^2 - 4
d) y = -1/3(x - 2)^2 + 4
e) y = -(x+2/3)^2 - 4
f) y = -(x-2/3)^2 - 4
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High School Teacher
We are given a parabola with vertex (-2,-4) that includes the point (1,-5), and we are asked to find the equation for the parabola.
The vertex form for a parabola is `y=a(x-h)^2+k` where the vertex is at (h,k) and a indicates whether the parabola opens up or down and how wide. (From the parent function `y=x^2` h performs a horizontal translation, k a vertical translation, and a a dilation.)
Here h=-2, k=-4 so it remains to find a:
Substitute the known values from the point (1,-5),h, and k into the equation and solve for a:
So the equation is `y=-1/9(x+2)^2-4` .
Scanning the list for an equivalent equation we note that b,d,and f cannot be the answer as h is wrong.
Answer A has a=-9, answer C has `a=-1/3` so these are wrong leaving only (e).
Rewrite `-1/9(x+2)^2-4` as `-(1/9(x+2)^2)-4=-(((x+2)^2)/9)-4`
`=-((x+2)/3)^2-4` which is answer (e).
Posted by embizze on September 22, 2013 at 2:38 AM (Answer #1)
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