Better Students Ask More Questions.
If `sqrt (x+3) + sqrt (x-2) = 5` , then the value of x is ____ ?This is a question I...
1 Answer | add yours
High School Teacher
`sqrt(x+3) + sqrt(x-2) = 5`
To remove the radicals, perform the opposite operation of square root. So, take the square of both sides.
`(sqrt(x+3) + sqrt(x-2))^2 = 5^2`
`x+3 + 2sqrt(x+3)*sqrt(x-2) + x-2=25`
Then, isolate the radical term.
Take the square of both sides again to eliminate the radicals.
Note that the terms `4x^2` appears on both sides of the equation. So if we move the `4x^2` from the right to left, the resulting expression is:
Then, bring together the terms with x on one side of the equation. Also, bring together the terms without x on the opposite side of the equation.
Then, isolate x.
Hence, the value of x is 6.
Posted by mjripalda on October 10, 2012 at 11:35 AM (Answer #1)
Join to answer this question
Join a community of thousands of dedicated teachers and students.