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Solve the quadratic equation by factoring: 2x^2+14=0

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rosey-girl | Student, Grade 12 | (Level 1) Valedictorian

Posted February 27, 2013 at 4:20 AM via web

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Solve the quadratic equation by factoring: 2x^2+14=0

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durbanville | High School Teacher | (Level 1) Educator Emeritus

Posted February 27, 2013 at 4:39 AM (Answer #1)

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`2x^2 + 14 =0`

`2(x^2 +7)= 0`

As the equation is equal to zero, each factor equals zero.  Thus:

`2!=0` 

`x^2+7=0`

`therefore x^2=-7`

`therefore x= +- sqrt (-7)`

`therefore` thre is no  normal solution for this equation due to the negative symbol inside the square root.

`therefore` no solution or if you use complex numbers = `isqrt7`

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted February 27, 2013 at 4:45 AM (Answer #2)

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The quadratic equation 2x^2+14=0 has to be solved.

2x^2+14=0

=> 2(x^2 + 7 ) = 0

x^2 + 7 = 0

=> x^2 = -7

=> x = `sqrt(-7)` and x = `-sqrt(-7)`

=> x = `sqrt7*i` and x = `-sqrt7*i`

The solution of the equation 2x^2+14=0 is x = `sqrt7*i ` and `x = -sqrt 7*i`

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