# solve for x and y : 3x-7y = -12 2x+4y = 3

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3x -7y = -12..........(1)

2x+4y = 3.............(2)

We need to find x and y by solving the system.

We will use the elimination method to find x and y.

We will multiply (1) with -2 and (2) with 3.

==> -2*(1) ==> -6x +14y = 24

==> 3 *(2) ==> 6x + 12y = 9

Now we will add both equations.

==> 26y= 33

==> y= 33/26

==> Now we will substitute into (2) to find x.

==> 2x + 4y = 3

==> 2x + 4( 33/26) = 3

==> 2x + 132/26 = 3

==> 2x = 3- 132/26 = -54/26

==> x = -54/52 =-27/26

**Then the answer is the pair ( -27/26, 33/26)**

The system of equations 3x-7y = -12 and 2x+4y = 3 has to be solved.

From 2x + 4y = 3, express x in terms of y. This gives:

2x = 3 - 4y

x = (3 - 4y)/2

Substitute for x in the equation 3x - 7y = -12

3*(3 - 4y)/2 - 7y = -12

9 - 12y - 14y = -24

-26y = -33

y = 33/26

x = (3 - 4y)/2

= (3 - 4*33/26)/2

= (-54/26)/2

= -27/26

The solution of the given system of equations is x = -27/26 and y = 33/26