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Solve for x. log (base 7) 5x-1 = log (base 7) x+7
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High School Teacher
`log_7 (5x-1)=log_7 (x+7)`
`log_7 x-log_7 y=log_7(x/y)`
Thus answer is
Posted by aruv on August 20, 2013 at 5:51 PM (Answer #1)
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