Homework Help

Solve for x. 3x^3+x^2-48x=16

user profile pic

kristenmarieb... | Student, Grade 10 | (Level 1) Valedictorian

Posted March 9, 2013 at 4:48 AM via web

dislike 1 like

Solve for x.

3x^3+x^2-48x=16

1 Answer | Add Yours

user profile pic

justaguide | College Teacher | (Level 2) Distinguished Educator

Posted March 9, 2013 at 4:54 AM (Answer #1)

dislike 1 like

The equation 3x^3+x^2-48x=16 has to be solved for x.

3x^3+x^2-48x=16

=> 3x^3+x^2-48x - 16 = 0

=> x^2(3x + 1) - 16(3x + 1) = 0

=> (x^2 - 16)(3x + 1) = 0

=> (x - 4)(x + 4)(3x + 1) = 0

x = 4, x = -4 and x = -1/3

The solution of the equation 3x^3+x^2-48x=16 is {-4, -1/3, 4}

Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes