# Solve for x: x^2 = 27

### 3 Answers | Add Yours

We have to solve x^2 = 27 for x.

x^2 = 27

=> x^2 = 9*3

=> x^2 = 3^2 * 3

=> x = 3* sqrt 3 and - 3*sqrt 3

**The required value is x = 3* sqrt 3 and x = -3*sqrt 3**

We'll have to solve the quadratic equation:

x^2 = 27

We'll take square root both sides:

sqrt x^2 = sqrt 27

We'll write 27 = 3^3 = 3*3^2

|x| = 3sqrt3

**The solutions of the equation are: {-3sqrt3 ; +3sqrt3}.**

There are two answers…

x² = 27 27 can be expressed as a factor of perfect square 9 and 3

x² = 9*3 , by extracting the square root, we get both + and - solutions

Square root of 9 is +3 , square root of 3 is not perfect whole, so we can leave it as is

x = 3 ±√3

x = 3√3, -3√3

x = 5.196152423, -5.196152423.