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solve for the TWO values of x that satisfy the equation...
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High School Teacher
Since by definition cosecant is `csc z=1/sin z` we have
Since `2sin z cos z=sin(2z)` we have
Now we take quare root and get two solutions
`x=-60^o + k720^o` <-- First solution
`x/2=210^o + k360^o`
`x=420^o +k720^o` <-- Second solution
`x=60^o + k720^o" <--Third solution"`
`x=300^o +k720^o" <-- Fourth solution"`
Now since first and second solution don't lie between 0° and 360° you have only two solutions and they are 60° and 300°.
Posted by tiburtius on May 6, 2013 at 5:20 PM (Answer #1)
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