Solve this equation using the quadratic formula:  (2x-3)^2 - 14 = 2x(x-7)



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Posted on (Answer #1)

First, we need to simpify the equation to standard form `(ax^2+bx+c)` :

Expand the squared term:


Next expand the multiplication:


Finally, move all terms to the left side and collect like terms:



We can now solve for the roots of this equation using the quadratic formula:

`x=(-b+-sqrt(b^2-4ac)) /(2a)`

a=2; b=2; c=-5

`x=(-2+-sqrt(2^2-4(2)(-5))) /(2(2))`


`x_1=(-2+sqrt(44))/4 =1.16`  


Graph of the function:

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