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Solve this equation: `tan^2 x - 3tan x + 2 = 0`
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High School Teacher
Note that this is quadratic in tan(x).
Thus we can factor as (tanx-2)(tanx-1)=0
By the zero product property we have
(1) tanx=1 ==> `x=pi/4 +kpi` for integer k
(2) tanx=2 ==> `x=tan^(-1)2~~1.107+kpi`
Posted by embizze on April 20, 2013 at 1:03 AM (Answer #2)
So ,equation reduces to
`` either y=2 or y=1
`x=npi+(7pi)/20` ,where n is an integer.
`x=n_1pi+pi/4` ,where `n_1` is an integer.
Posted by pramodpandey on April 20, 2013 at 11:46 AM (Answer #4)
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