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Solve the system: y^2 - x^2 = 9 2x - y = 3
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Let `y^2 - x^2 = 9` ..........eq. (i)
`2x - y = 3` .........eq.(ii)
From (ii) we get:
Substituting `y=2x-3` in eq. (i) we get:
So, either x=0 or x=4
Now plug in the values of x in eq.(ii) to get the corresponding values of y.
So, when x=0 `y=2*0-3=-3`
When x=4 `y=2*4-3=5`
Therefore, the solutions are (0,-3) and (4,5).
Posted by llltkl on July 14, 2013 at 4:10 AM (Answer #1)
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