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solve: log8 x=2/3

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solve: log8 x=2/3

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Solve `log_8 x=2/3` :

An equivalent equation is `x=8^(2/3)` .

The cube root of 8 is 2 and 2^2 is 4 so `x=8^(2/3)=2^2=4`

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`log_8 x =2/3 ==> x=4`

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Check: Use the change of base formula.

`log_8 4= (ln(4))/ln(8)=2/3` as required.

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