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What is `int x*e^(-x^2) dx`
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`int xe^(-x^2) dx= -1/2 int -2xe^(-x^2) dx= -1/2 int d e^(-x^2)=-1/2 e^(-x^2)`
Posted by oldnick on May 30, 2013 at 3:18 AM (Answer #2)
We have to find the value of : `int x*e^(-x^2) dx`
Let -x^2 = y
dy/dx = -2x
x*dx = (-1/2)*dy
`int x*e^(-x^2) dx`
=> `int (-1/2)*e^y dy`
substitute y = -x^2
The required integral is `-1/(2*e^(x^2))`
Posted by justaguide on October 28, 2011 at 5:46 PM (Answer #1)
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