Solve the inequality: SQRT (3x - 2)2 < 5

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SQRT(3x-2)*2<5

SQRT(3x-2)<5/2

3x-2 < (2.5)^2

3x < 6.25+2

x < 8.25/3

**x < 2.75**

Given the equation:

sqrt(3x-2)^2 < 5

Now we will rewrite using the absolute value form.

==> l 3x-2 l < 5

Now we will rewrite :

-5 < 3x-2 < 5

Now we will add 2 to both sides.

==> -3 < 3x < 7

Now we will divide by 3.

==> -1 < x < 7/3

**Then the answer is: x= ( -1, 7/3).**

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