# Solve the following simultaneous equations. x + 3y = 2 , 2x + 8y = 6

justaguide | College Teacher | (Level 2) Distinguished Educator

Posted on

We have to solve the following set of simultaneous equations:

x + 3y = 2 ...(1)

2x + 8y = 6 ...(2)

2*(1) - (2)

=> 2x + 6y - 2x - 8y = 4 - 6

=> -2y = -2

=> y = -2/-2

=> y = 1

substitute in (1)

x + 3 = 2

=> x = 2 - 3

=> x = -1

We get x = -1 and y = 1

givingiswinning | Student, Grade 10 | (Level 1) Valedictorian

Posted on

x + 3y = 2

x = 2 - 3y

plug it in as x into the other equation:

2(2 - 3y) + 8y = 6

4 - 6y + 8y = 6

bring like terms to the same side:

-6y + 8y = 6 - 4

combine:

2y = 2

divide by 2

y = 1

x + 3(1) = 2

x + 3 = 2

subtract 3

x = 2 - 3

x = -1
(-1 , 1)

atyourservice | Student, Grade 11 | (Level 3) Valedictorian

Posted on

x + 3y = 2

x = 2 - 3y

plug it in as x into the other equation:

2(2 - 3y) + 8y = 6

4 - 6y + 8y = 6

bring like terms to the same side:

-6y + 8y = 6 - 4

combine:

2y = 2

divide by 2

• y = 1

now plug that into any of the problems:

x + 3(1) = 2

x + 3 = 2

subtract 3

x = 2 - 3

• x = -1

(-1 , 1)

giorgiana1976 | College Teacher | (Level 3) Valedictorian

Posted on

We'll solve the system using substitution method and we'll write x from the 1st equation, with respect to y:

x = 2 - 3y

We'll substitute x in the 2nd equation:

2(2 - 3y) + 8y = 6

We'll remove the brackets:

4 - 6y + 8y = 6

We'll combine like terms:

2y = 6 - 4

2y = 2

y  = 1

We'll substitute y in the first equation:

x + 3 = 2

x = 2  - 3

x = -1

The solution of the system is represented by the pair (-1 ; 1).