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Solve the following inequality algebraically `|(x+3)/(x-1)| > 1`

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spock12 | Student, Undergraduate | eNoter

Posted May 26, 2012 at 7:50 PM via web

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Solve the following inequality algebraically `|(x+3)/(x-1)| > 1`

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thilina-g | College Teacher | (Level 1) Educator

Posted May 26, 2012 at 8:51 PM (Answer #1)

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`|(x+3)/(x-1)|gt1`

This will give two initial solutions,

`(x+3)/(x-1) gt 1` or `(x+3)/(x-1) lt-1`

1) `(x+3)/(x-1) gt 1`

`(x+3)/(x-1)-1 gt 0`

`(x+3-(x-1))/(x-1) gt0 `

This gives,

`4/(x-1)gt0`

`1/(x-1) gt0`

Multiplying both denominator and numerator by (x-1),

`(x-1)/(x-1)^2 gt0`

This would make the denominator alway positive, and the requirement for this inequality would be,

`x-1gt0`

`x gt1`

 

2)`(x+3)/(x-1) lt-1`

`(x+3)/(x-1) +1 lt 0`

This gives,

`(x+3+x-1)/(x-1)lt0`

`(2x+2)/(x-1) lt 0`

`(x+1)/(x-1) lt 0`

Multiplying both denominator and numerator by (x-1),

`((x+1)(x-1))/(x-1)^2 lt0`

 

This gives,

(x+1)(x-1) < 0

The solution for this is -1<x<1

 

By combining above two solutions we can get the final solution.

Therefore the required solution for `|(x+3)/(x-1)|gt1` is `xgt -1` .

 

The answer is x > -1

 

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