Solve the following inequalities: x^2+5x+12 > 6
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Changing into factors,
For this to be positive, both of the factors are negative or both of the factors are positive.
Therefore, one solution is,
`x+2lt0 and x+3lt0`
`xlt-2` and `xlt-3`
The common solution for this is `x lt-3` .
The other solution,
`x+2gt0` and `x+3gt0`
`xgt-2` and `xgt-3` .
The common solution is `xgt-2` .
Therefore, the solutions for the given inequaility are x <-3 or x>-2.
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