# Solve the equations x = 8y + 1 and x^2 = 2y - 2

### 1 Answer | Add Yours

`x = 8y+1`

`x^2 = (8y+1)^2`

But;

`x^2 = 2y-2`

`(8y+1)^2 = 2y-2`

`64y^2+16y+1 = 2y-2`

`64y^2+14y+3 = 0`

The solution of the above equation is;

`y = (-14+-sqrt(14^2-4*64*3))/(2*64)`

`y = -7/64`

Therefore

`x = 8y+1 = 8*(-7/64)+1 = 1/8`

*So the answers are;*

`x = 1/8`

`y = -7/64`