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Solve equation xC3=5/4x(x-3)? combination C
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`^nC_r = (n!)/[(r!)(n-r)!]`
`^xC_3 = (x!)/[3!(x-3)!]`
` (x!)/[3!(x-3)!] = (5/4)x(x-3)`
Posted by jeew-m on September 1, 2012 at 2:30 PM (Answer #1)
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