Solve the equation sinx=1/5.



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Posted on (Answer #1)

This is an elementary trigonometric equation and we'll use the following pattern to solve it:

sin x = a

x = ` ``(-1)^(k)` arcsin a + `pi` *k

Let a = 1/5

Since 1/5 < 1, therefore there are values of x for the sine function to be possible.

sin x = 1/5

x = `(-1)^(k)` arcsin (1/5) + `pi` *k

x = `(-1)^(k)` *11.53 + `pi` *k

The solutions of the equation belong to the set {`(-1)^(k)`11.53 + `pi` *k/ k`in`Z }.

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