# Solve the equation 3x^2 - 4x + 8 = 0

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The equation 3x^2 - 4x + 8 = 0 has to be solved. The roots of a quadratic equation ax^2 + bx + c = 0 are `x1 = (-b + sqrt(b^2 - 4ac))/(2a)` and `x2 = (-b - sqrt(b^2 - 4ac))/(2a)`

For the given equation the roots are

x1 = `(4 + sqrt(16 - 96))/6`

= `2/3 + (2*sqrt 5*i)/3`

x2 = `2/3 - (2*sqrt 5*i)/3`

**The solutions of the equation 3x^2 - 4x + 8 = 0 are `2/3 + (2*sqrt 5*i)/3` and `2/3 - (2*sqrt 5*i)/3` **