Solve each quadratic system.
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We solve this system of quadratic equations by method of substitution.
so from (ii)
`x^2=4+y^2` (iii) ,substitute this value of `x^2` in (i),thus we have
substitute y=0 in (iii) , we have
Thus solution of system of equations are
subtract at (1) (2) multiplied by 9:
`13y^2=0` `rArr y=0`
On the other side:
Adding at (1) (2) multiplied by 4:
`13x^2=52` `rArr` `y^2=4` `rArr x=+-2`
Solutions are `(+-2;0)`
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