# Solve by using the quadratic formula 3x^2 + 6x + 2 = 0

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Solve `3x^2 + 6x + 2` by using the quadratic formula.

Quadratic formula: `(-b+-sqrt(b^2-4ac))/2a`

a = 3, b = 6, c = 2

`(-6+-sqrt(6^2-4(3)(2)))/(2(3))`

`(-6+-sqrt(36 - 24))/6`

` ` `(-6+-sqrt(12))/6`

`(-6+-2sqrt(3))/6` Cancel 2 out of every term.

`(-3+-sqrt(3))/3` or `-1+-(sqrt(3)/3)`