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But when you multiply both sides of an inequality by a negative number, you reverse the inequality. So the answer is v>5
Note this example, if answer were v < 5 :
then -4 -(5x1)<-29
-4 - 5 < -29
-9 < -29--which is not true.
But suppose v is a number greater than 5, like 6:
-4 - (5x6) < -29
-4 - (30) < -29
-34 < -29.
and just to be sure, let's make sure v cannot equal 5:
-4 - (5-5) < -29
-4 - (0) < -29
-4 < -29--not true, so that's settled.
To recap then, solve -4 - 5v < -29 like this:
-4 - (5v) < -29
-5v < -29 +4
-5v < -25
(-1/5)5v < -25(-1/5)
when multiplying both sides of an inequality by a negative number, you need to flip the inequality
v > 5
-4-5v<-29 you first cancelled the -4 by adding +4 then you do the same to the other side by adding 4 to -29 = -25
-5v<-25 Then you divide by -5 to both sides by you need to change the symbol because you are dividing a negative
okay so you want to try to isolate the v, or the unkown variable by itself in order to do this you would add 4 to both sides (remember what you do to one side of the equal sign or > or< sign, you must do to the other
then divide by -5, but when you have > or< signs, when you divide by a negitive number, you must flip the sign
so it would be v>5.
-4 - 5v < -29
First you can imaging " < " as an " = " sign
So you should add 4 on both sides
By adding on both sides, you should get
-5v < -25 now divide both sides by -5
By dividing, your equation should look like
v > 5 which is your answer
now remember that for equation that has signs " > " or " < " if you divide or multiply, then you have to switch the sign
To solve this inequality you must first isolate the variable. To do this you must add +4 to each side. After this is done you will be left with -5v<-25. The next step will be to divide each side by -5. -5/-5v < -25/-5. Following this step you will have your answer. V< 5.
Thus, negative 4 plus a negative 5V is any number less than a negative 25. Your solution is V is any number less than 5.
-5v < -29 + 4
-5v < -25
v > -25/5 (Sign change so flip the inequality sign!)
v > -5
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